{"id":17970,"date":"2024-04-05T03:01:39","date_gmt":"2024-04-05T03:01:39","guid":{"rendered":"https:\/\/soicau5098.minhngocxoso.com\/?p=17970"},"modified":"2024-04-05T03:01:39","modified_gmt":"2024-04-05T03:01:39","slug":"bat-mi-soi-cau-de-bang-phuong-phap-3-cay","status":"publish","type":"post","link":"https:\/\/loto3cang.com\/bat-mi-soi-cau-de-bang-phuong-phap-3-cay\/","title":{"rendered":"b\u1eadt m\u00ed soi c\u1ea7u \u0111\u1ec1 b\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p 3 c\u00e2y"},"content":{"rendered":"\n
Soi c\u1ea7u \u0111\u1ec1 b\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p 3 c\u00e2y \u2013 B\u1ea1n \u0111\u00e3 bi\u1ebft ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh l\u00f4 \u0111\u1ec1 hi\u1ec7u qu\u1ea3 n\u00e0o ch\u01b0a? Trong b\u00e0i vi\u1ebft n\u00e0y s\u1ebd gi\u1edbi thi\u1ec7u \u0111\u1ebfn c\u00e1c b\u1ea1n chi ti\u1ebft ph\u01b0\u01a1ng ph\u00e1p b\u1eaft \u0111\u1ec1 3 c\u00e2y \u0111\u00e3 \u0111\u01b0\u1ee3c nhi\u1ec1u b\u1ea1n \u00e1p d\u1ee5ng th\u00e0nh c\u00f4ng.<\/p>\n\n\n\n
V\u00ed d\u1ee5: X\u1ebfp 2 s\u1ed1 \u0111\u1ec1 ra trong hai ng\u00e0y 1 v\u00e0 2.<\/p>\n\n\n\n
Ng\u00e0y 1 \u0111\u1ec1 ra 32<\/p>\n\n\n\n
Ng\u00e0y 2 \u0111\u1ec1 ra 22<\/p>\n\n\n\n
\u1ede ph\u01b0\u01a1ng ph\u00e1p n\u00e0y gi\u00fap b\u1ea1n soi c\u1ea7u s\u1ed1 \u0111\u1ec1 ra ng\u00e0y ti\u1ebfp theo \u0111\u00f3 l\u00e0 ng\u00e0y 3 \u0111\u1ec1 ra XX. \u0110\u1ec3 t\u00ecm ra \u0111\u01b0\u1ee3c s\u1ed1 X, ch\u00fang ta c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p c\u1ed9ng b\u00f9: Ng\u01b0\u1eddi ch\u01a1i l\u1ea5y m\u1ed9t ch\u1eef s\u1ed1 c\u1ee7a ng\u00e0y th\u1ee9 1 c\u1ed9ng v\u1edbi m\u1ed9t ch\u1eef s\u1ed1 c\u1ee7a ng\u00e0y th\u1ee9 2 v\u00e0 c\u1ed9ng v\u1edbi X sao cho k\u1ebft qu\u1ea3 b\u1eb1ng 10 ho\u1eb7c b\u1eb1ng 20.<\/p>\n\n\n\n
V\u1edbi v\u00ed d\u1ee5 tr\u00ean ta c\u00f3 3+2+X=10 ho\u1eb7c 20 ->X=5<\/p>\n\n\n\n
2+2+X = 10 ho\u1eb7c 20 -> X=6<\/p>\n\n\n\n
V\u1eady 56-65 l\u00e0 s\u1ed1 c\u1ea7n t\u00ecm \u0111\u1ec3 ch\u01a1i \u0111\u1ec1.<\/p>\n\n\n\n V\u00ed d\u1ee5:<\/p>\n\n\n\n Ng\u00e0y 1 k\u1ebft qu\u1ea3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t: 58432 ta l\u1ea5y 52<\/p>\n\n\n\n Ng\u00e0y 2 k\u1ebft qu\u1ea3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t: 73122 ta l\u1ea5y 72<\/p>\n\n\n\n Ph\u01b0\u01a1ng ph\u00e1p 3 c\u00e2y \u0111\u00e1nh l\u00f4 \u0111\u1ec1 nh\u01b0 sau:<\/p>\n\n\n\n 5+7+X = 10 ho\u1eb7c 20 -> X=8<\/p>\n\n\n\n 5+2+X = 10 ho\u1eb7c 20 -> X=3<\/p>\n\n\n\n 2+7+X = 10 ho\u1eb7c 20 -> X=1<\/p>\n\n\n\n 2+2+X = 10 ho\u1eb7c 20 -> X=6<\/p>\n\n\n\n Nh\u01b0 v\u1eady v\u1edbi ph\u01b0\u01a1ng ph\u00e1p t\u00ednh nh\u01b0 tr\u00ean ch\u00fang ta c\u00f3 th\u1ec3 d\u1ec5 d\u00e0ng t\u00ecm ra c\u00e1c k\u1ebft qu\u1ea3 X t\u1eeb v\u00ed d\u1ee5 l\u00e0 nh\u1eefng s\u1ed1 1, 3, 5, 6, 8 \u0111\u1ec3 \u1ee9ng d\u1ee5ng v\u00e0o b\u1eaft con \u0111\u1ec1 s\u1ebd v\u1ec1 trong ng\u00e0y 17\/09. L\u01b0u \u00fd \u0111\u1ebfn nh\u1eefng con s\u1ed1 tr\u00f9ng nhau v\u00e0 th\u01b0\u1eddng s\u1ebd c\u00f3 1-3 con s\u1ed1 \u0111\u00f3, k\u1ebft qu\u1ea3 v\u1ec1 nh\u01b0 th\u1ebf n\u00e0o b\u1ea1n c\u0169ng bi\u1ebft r\u1ed3i \u0111\u00f3.<\/p>\n\n\n\n V\u1edbi ph\u01b0\u01a1ng ph\u00e1p tr\u00ean, n\u1ebfu b\u1ea1n \u00e1p d\u1ee5ng thu\u1ea7n th\u1ee5c, b\u1ea1n s\u1ebd ki\u1ebfm v\u1ec1 kh\u00f4ng \u00edt l\u1ee3i nhu\u1eadn r\u1ed3i, n\u00ean \u0111i t\u1eeb c\u00e1i d\u1ec5 tr\u01b0\u1edbc b\u1ea1n nh\u00e9. Ch\u00fac c\u00e1c b\u1ea1n ch\u01a1i vui v\u1ebb.<\/p>\n\r\n2. L\u1ea5y 2 s\u1ed1 \u0111\u1ea7u v\u00e0 2 s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t hai ng\u00e0y g\u1ea7n nh\u1ea5t<\/strong><\/h3>\n\n\n\n
KHU V\u1ef0C CH\u1ed0T S\u1ed0 SI\u00caU V\u00cdP<\/b><\/span><\/h3>\r\n